16v2+10=6+12v2-8v

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Solution for 16v2+10=6+12v2-8v equation: 



16v^2+10=6+12v^2-8v

We move all terms to the left:

16v^2+10-(6+12v^2-8v)=0

We get rid of parentheses

16v^2-12v^2+8v-6+10=0

We add all the numbers together, and all the variables

4v^2+8v+4=0

a = 4; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-8}{8}=-1$

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