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16v=(4v-2)=3
We move all terms to the left:
16v-((4v-2))=0
We calculate terms in parentheses: -((4v-2)), so:We get rid of parentheses
(4v-2)
We get rid of parentheses
4v-2
Back to the equation:
-(4v-2)
16v-4v+2=0
We add all the numbers together, and all the variables
12v+2=0
We move all terms containing v to the left, all other terms to the right
12v=-2
v=-2/12
v=-1/6
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