16v=(4v-2)=3

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Solution for 16v=(4v-2)=3 equation: 



16v=(4v-2)=3

We move all terms to the left:

16v-((4v-2))=0



We calculate terms in parentheses: -((4v-2)), so:

(4v-2)

We get rid of parentheses

4v-2

Back to the equation:

-(4v-2)



We get rid of parentheses

16v-4v+2=0

We add all the numbers together, and all the variables

12v+2=0

We move all terms containing v to the left, all other terms to the right

12v=-2

v=-2/12

v=-1/6

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