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16x(2)=x+17
We move all terms to the left:
16x(2)-(x+17)=0
We add all the numbers together, and all the variables
16x^2-(x+17)=0
We get rid of parentheses
16x^2-x-17=0
We add all the numbers together, and all the variables
16x^2-1x-17=0
a = 16; b = -1; c = -17;
Δ = b2-4ac
Δ = -12-4·16·(-17)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-33}{2*16}=\frac{-32}{32} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+33}{2*16}=\frac{34}{32} =1+1/16 $
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