16x(4x-10)=0

Solution for 16x(4x-10)=0 equation:

16x(4x-10)=0

We multiply parentheses

64x^2-160x=0

a = 64; b = -160; c = 0;
Δ = b2-4ac
Δ = -1602-4·64·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-160}{2*64}=\frac{0}{128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+160}{2*64}=\frac{320}{128}
=2+1/2
$