16x(8-x)=192

Solution for 16x(8-x)=192 equation:

16x(8-x)=192

We move all terms to the left:

16x(8-x)-(192)=0

We add all the numbers together, and all the variables

16x(-1x+8)-192=0

We multiply parentheses

-16x^2+128x-192=0

a = -16; b = 128; c = -192;
Δ = b2-4ac
Δ = 1282-4·(-16)·(-192)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-64}{2*-16}=\frac{-192}{-32}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+64}{2*-16}=\frac{-64}{-32}
=+2
$