16x(x+1)=0

Solution for 16x(x+1)=0 equation:

16x(x+1)=0

We multiply parentheses

16x^2+16x=0

a = 16; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·16·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*16}=\frac{0}{32}
=0
$