16x(x+1)=8x-1

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Solution for 16x(x+1)=8x-1 equation: 



16x(x+1)=8x-1

We move all terms to the left:

16x(x+1)-(8x-1)=0

We multiply parentheses

16x^2+16x-(8x-1)=0

We get rid of parentheses

16x^2+16x-8x+1=0

We add all the numbers together, and all the variables

16x^2+8x+1=0

a = 16; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{32}=-1/4$

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