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16x(x+10)=x(x+10)
We move all terms to the left:
16x(x+10)-(x(x+10))=0
We multiply parentheses
16x^2+160x-(x(x+10))=0
We calculate terms in parentheses: -(x(x+10)), so:We get rid of parentheses
x(x+10)
We multiply parentheses
x^2+10x
Back to the equation:
-(x^2+10x)
16x^2-x^2+160x-10x=0
We add all the numbers together, and all the variables
15x^2+150x=0
a = 15; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·15·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*15}=\frac{-300}{30} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*15}=\frac{0}{30} =0 $
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