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16x(x+5)=5
We move all terms to the left:
16x(x+5)-(5)=0
We multiply parentheses
16x^2+80x-5=0
a = 16; b = 80; c = -5;
Δ = b2-4ac
Δ = 802-4·16·(-5)
Δ = 6720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6720}=\sqrt{64*105}=\sqrt{64}*\sqrt{105}=8\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-8\sqrt{105}}{2*16}=\frac{-80-8\sqrt{105}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+8\sqrt{105}}{2*16}=\frac{-80+8\sqrt{105}}{32} $
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