16x+1-4x=2(4+3x)

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Solution for 16x+1-4x=2(4+3x) equation: 



16x+1-4x=2(4+3x)

We move all terms to the left:

16x+1-4x-(2(4+3x))=0

We add all the numbers together, and all the variables

16x-4x-(2(3x+4))+1=0

We add all the numbers together, and all the variables

12x-(2(3x+4))+1=0



We calculate terms in parentheses: -(2(3x+4)), so:

2(3x+4)

We multiply parentheses

6x+8

Back to the equation:

-(6x+8)



We get rid of parentheses

12x-6x-8+1=0

We add all the numbers together, and all the variables

6x-7=0

We move all terms containing x to the left, all other terms to the right

6x=7

x=7/6

x=1+1/6

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