16x+12x2=51

Solution for 16x+12x2=51 equation:

16x+12x^2=51

We move all terms to the left:

16x+12x^2-(51)=0

a = 12; b = 16; c = -51;
Δ = b2-4ac
Δ = 162-4·12·(-51)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-52}{2*12}=\frac{-68}{24}
=-2+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+52}{2*12}=\frac{36}{24}
=1+1/2
$