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16x+22=4(3x+5)+4x+2
We move all terms to the left:
16x+22-(4(3x+5)+4x+2)=0
We calculate terms in parentheses: -(4(3x+5)+4x+2), so:We get rid of parentheses
4(3x+5)+4x+2
We add all the numbers together, and all the variables
4x+4(3x+5)+2
We multiply parentheses
4x+12x+20+2
We add all the numbers together, and all the variables
16x+22
Back to the equation:
-(16x+22)
16x-16x-22+22=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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