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16x+30=3(8/3x+2)
We move all terms to the left:
16x+30-(3(8/3x+2))=0
Domain of the equation: 3x+2))!=0We multiply all the terms by the denominator
x∈R
16x*3x+30*3x+2))-(3(8+2))=0
We add all the numbers together, and all the variables
16x*3x+30*3x+2))-(310)=0
We add all the numbers together, and all the variables
16x*3x+30*3x=0
Wy multiply elements
48x^2+90x=0
a = 48; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·48·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*48}=\frac{-180}{96} =-1+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*48}=\frac{0}{96} =0 $
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