16x+33=81+4x

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Solution for 16x+33=81+4x equation: 



16x+33=81+4x

We move all terms to the left:

16x+33-(81+4x)=0

We add all the numbers together, and all the variables

16x-(4x+81)+33=0

We get rid of parentheses

16x-4x-81+33=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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