16x-(1/x)=0

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Solution for 16x-(1/x)=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

16*x-(1/x) = 0

16*x-x^-1 = 0

16*x^1-1*x^-1 = 0

(16*x^2-1*x^0)/(x^1) = 0 // * x^2

x^1*(16*x^2-1*x^0) = 0

x^1

16*x^2-1 = 0

16*x^2-1 = 0

DELTA = 0^2-(-1*4*16)

DELTA = 64

DELTA > 0

x = (64^(1/2)+0)/(2*16) or x = (0-64^(1/2))/(2*16)

x = 1/4 or x = -1/4

x in { -1/4, 1/4}

x in { -1/4, 1/4 }

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