16x-(3x-2)=67

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Solution for 16x-(3x-2)=67 equation: 



16x-(3x-2)=67

We move all terms to the left:

16x-(3x-2)-(67)=0

We get rid of parentheses

16x-3x+2-67=0

We add all the numbers together, and all the variables

13x-65=0

We move all terms containing x to the left, all other terms to the right

13x=65

x=65/13

x=5

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