16x-(8+4x)=12x-8

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Solution for 16x-(8+4x)=12x-8 equation: 



16x-(8+4x)=12x-8

We move all terms to the left:

16x-(8+4x)-(12x-8)=0

We add all the numbers together, and all the variables

16x-(4x+8)-(12x-8)=0

We get rid of parentheses

16x-4x-12x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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