16x-(x-3)=3-3(2x+4)

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Solution for 16x-(x-3)=3-3(2x+4) equation: 



16x-(x-3)=3-3(2x+4)

We move all terms to the left:

16x-(x-3)-(3-3(2x+4))=0

We get rid of parentheses

16x-x-(3-3(2x+4))+3=0



We calculate terms in parentheses: -(3-3(2x+4)), so:

3-3(2x+4)

determiningTheFunctionDomain
-3(2x+4)+3

We multiply parentheses

-6x-12+3

We add all the numbers together, and all the variables

-6x-9

Back to the equation:

-(-6x-9)



We add all the numbers together, and all the variables

15x-(-6x-9)+3=0

We get rid of parentheses

15x+6x+9+3=0

We add all the numbers together, and all the variables

21x+12=0

We move all terms containing x to the left, all other terms to the right

21x=-12

x=-12/21

x=-4/7

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