16x-114=(x+3)2

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Solution for 16x-114=(x+3)2 equation: 



16x-114=(x+3)2

We move all terms to the left:

16x-114-((x+3)2)=0



We calculate terms in parentheses: -((x+3)2), so:

(x+3)2

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

16x-2x-6-114=0

We add all the numbers together, and all the variables

14x-120=0

We move all terms containing x to the left, all other terms to the right

14x=120

x=120/14

x=8+4/7

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