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16x-3=4x+2
We move all terms to the left:
16x-3-(4x+2)=0
We get rid of parentheses
16x-4x-2-3=0
We add all the numbers together, and all the variables
12x-5=0
We move all terms containing x to the left, all other terms to the right
12x=5
x=5/12
x=5/12
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