16x-4(4x-3)=12

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Solution for 16x-4(4x-3)=12 equation: 


Simplifying
16x + -4(4x + -3) = 12

Reorder the terms:
16x + -4(-3 + 4x) = 12
16x + (-3 * -4 + 4x * -4) = 12
16x + (12 + -16x) = 12

Reorder the terms:
12 + 16x + -16x = 12

Combine like terms: 16x + -16x = 0
12 + 0 = 12
12 = 12

Add '-12' to each side of the equation.
12 + -12 = 12 + -12

Combine like terms: 12 + -12 = 0
0 = 12 + -12

Combine like terms: 12 + -12 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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