16x-4(8x+3)=4x+3(3x-2)

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Solution for 16x-4(8x+3)=4x+3(3x-2) equation: 



16x-4(8x+3)=4x+3(3x-2)

We move all terms to the left:

16x-4(8x+3)-(4x+3(3x-2))=0

We multiply parentheses

16x-32x-(4x+3(3x-2))-12=0



We calculate terms in parentheses: -(4x+3(3x-2)), so:

4x+3(3x-2)

We multiply parentheses

4x+9x-6

We add all the numbers together, and all the variables

13x-6

Back to the equation:

-(13x-6)



We add all the numbers together, and all the variables

-16x-(13x-6)-12=0

We get rid of parentheses

-16x-13x+6-12=0

We add all the numbers together, and all the variables

-29x-6=0

We move all terms containing x to the left, all other terms to the right

-29x=6

x=6/-29

x=-6/29

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