16x-40-12x+28=7

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Solution for 16x-40-12x+28=7 equation:



16x-40-12x+28=7
We move all terms to the left:
16x-40-12x+28-(7)=0
We add all the numbers together, and all the variables
4x-19=0
We move all terms containing x to the left, all other terms to the right
4x=19
x=19/4
x=4+3/4

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