16x2+10=131

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Solution for 16x2+10=131 equation:



16x^2+10=131
We move all terms to the left:
16x^2+10-(131)=0
We add all the numbers together, and all the variables
16x^2-121=0
a = 16; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·16·(-121)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*16}=\frac{-88}{32} =-2+3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*16}=\frac{88}{32} =2+3/4 $

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