16x2+10x-27=-6x+5

Solution for 16x2+10x-27=-6x+5 equation:

16x^2+10x-27=-6x+5

We move all terms to the left:

16x^2+10x-27-(-6x+5)=0

We get rid of parentheses

16x^2+10x+6x-5-27=0

We add all the numbers together, and all the variables

16x^2+16x-32=0

a = 16; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·16·(-32)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-48}{2*16}=\frac{-64}{32}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+48}{2*16}=\frac{32}{32}
=1
$