16x2+11x-11=0

Solution for 16x2+11x-11=0 equation:

16x^2+11x-11=0

a = 16; b = 11; c = -11;
Δ = b2-4ac
Δ = 112-4·16·(-11)
Δ = 825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{825}=\sqrt{25*33}=\sqrt{25}*\sqrt{33}=5\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5\sqrt{33}}{2*16}=\frac{-11-5\sqrt{33}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5\sqrt{33}}{2*16}=\frac{-11+5\sqrt{33}}{32}
$