16x2+14x-20=0

Solution for 16x2+14x-20=0 equation:

16x^2+14x-20=0

a = 16; b = 14; c = -20;
Δ = b2-4ac
Δ = 142-4·16·(-20)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{41}}{2*16}=\frac{-14-6\sqrt{41}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{41}}{2*16}=\frac{-14+6\sqrt{41}}{32}
$