16x2+150x+150=0

Solution for 16x2+150x+150=0 equation:

16x^2+150x+150=0

a = 16; b = 150; c = +150;
Δ = b2-4ac
Δ = 1502-4·16·150
Δ = 12900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12900}=\sqrt{100*129}=\sqrt{100}*\sqrt{129}=10\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-10\sqrt{129}}{2*16}=\frac{-150-10\sqrt{129}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+10\sqrt{129}}{2*16}=\frac{-150+10\sqrt{129}}{32}
$