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16x^2+316x-164=0
a = 16; b = 316; c = -164;
Δ = b2-4ac
Δ = 3162-4·16·(-164)
Δ = 110352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{110352}=\sqrt{1936*57}=\sqrt{1936}*\sqrt{57}=44\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(316)-44\sqrt{57}}{2*16}=\frac{-316-44\sqrt{57}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(316)+44\sqrt{57}}{2*16}=\frac{-316+44\sqrt{57}}{32} $
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