16x2+316x-183=0

Solution for 16x2+316x-183=0 equation:

16x^2+316x-183=0

a = 16; b = 316; c = -183;
Δ = b2-4ac
Δ = 3162-4·16·(-183)
Δ = 111568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{111568}=\sqrt{16*6973}=\sqrt{16}*\sqrt{6973}=4\sqrt{6973}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(316)-4\sqrt{6973}}{2*16}=\frac{-316-4\sqrt{6973}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(316)+4\sqrt{6973}}{2*16}=\frac{-316+4\sqrt{6973}}{32}
$