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16x^2+36=-48x
We move all terms to the left:
16x^2+36-(-48x)=0
We get rid of parentheses
16x^2+48x+36=0
a = 16; b = 48; c = +36;
Δ = b2-4ac
Δ = 482-4·16·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-48}{32}=-1+1/2$
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