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16x^2+50x+6=0
a = 16; b = 50; c = +6;
Δ = b2-4ac
Δ = 502-4·16·6
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-46}{2*16}=\frac{-96}{32} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+46}{2*16}=\frac{-4}{32} =-1/8 $
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