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16x^2+8x+1=16
We move all terms to the left:
16x^2+8x+1-(16)=0
We add all the numbers together, and all the variables
16x^2+8x-15=0
a = 16; b = 8; c = -15;
Δ = b2-4ac
Δ = 82-4·16·(-15)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*16}=\frac{-40}{32} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*16}=\frac{24}{32} =3/4 $
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