16x2+9x-6=0

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Solution for 16x2+9x-6=0 equation:



16x^2+9x-6=0
a = 16; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·16·(-6)
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{465}}{2*16}=\frac{-9-\sqrt{465}}{32} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{465}}{2*16}=\frac{-9+\sqrt{465}}{32} $

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