16x2-10x-16=0

Solution for 16x2-10x-16=0 equation:

16x^2-10x-16=0

a = 16; b = -10; c = -16;
Δ = b2-4ac
Δ = -102-4·16·(-16)
Δ = 1124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1124}=\sqrt{4*281}=\sqrt{4}*\sqrt{281}=2\sqrt{281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{281}}{2*16}=\frac{10-2\sqrt{281}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{281}}{2*16}=\frac{10+2\sqrt{281}}{32}
$