16x2-128x+192=0

Solution for 16x2-128x+192=0 equation:

16x^2-128x+192=0

a = 16; b = -128; c = +192;
Δ = b2-4ac
Δ = -1282-4·16·192
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-64}{2*16}=\frac{64}{32}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+64}{2*16}=\frac{192}{32}
=6
$