16x2-14x+3=0

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Solution for 16x2-14x+3=0 equation:



16x^2-14x+3=0
a = 16; b = -14; c = +3;
Δ = b2-4ac
Δ = -142-4·16·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*16}=\frac{12}{32} =3/8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*16}=\frac{16}{32} =1/2 $

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