16x2-16=0

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Solution for 16x2-16=0 equation:



16x^2-16=0
a = 16; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·16·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*16}=\frac{-32}{32} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*16}=\frac{32}{32} =1 $

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