16x2-16x+4=0

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Solution for 16x2-16x+4=0 equation: 



16x^2-16x+4=0

a = 16; b = -16; c = +4;
Δ = b2-4ac
Δ = -162-4·16·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{32}=1/2$

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