16x2-18x-2=0

Solution for 16x2-18x-2=0 equation:

16x^2-18x-2=0

a = 16; b = -18; c = -2;
Δ = b2-4ac
Δ = -182-4·16·(-2)
Δ = 452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{452}=\sqrt{4*113}=\sqrt{4}*\sqrt{113}=2\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{113}}{2*16}=\frac{18-2\sqrt{113}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{113}}{2*16}=\frac{18+2\sqrt{113}}{32}
$