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16x^2-4900=0
a = 16; b = 0; c = -4900;
Δ = b2-4ac
Δ = 02-4·16·(-4900)
Δ = 313600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{313600}=560$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-560}{2*16}=\frac{-560}{32} =-17+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+560}{2*16}=\frac{560}{32} =17+1/2 $
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