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16x^2-54=0
a = 16; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·16·(-54)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{6}}{2*16}=\frac{0-24\sqrt{6}}{32} =-\frac{24\sqrt{6}}{32} =-\frac{3\sqrt{6}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{6}}{2*16}=\frac{0+24\sqrt{6}}{32} =\frac{24\sqrt{6}}{32} =\frac{3\sqrt{6}}{4} $
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