16x2-8x-48=0

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Solution for 16x2-8x-48=0 equation:



16x^2-8x-48=0
a = 16; b = -8; c = -48;
Δ = b2-4ac
Δ = -82-4·16·(-48)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-56}{2*16}=\frac{-48}{32} =-1+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+56}{2*16}=\frac{64}{32} =2 $

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