16x2-96x+137=0

Solution for 16x2-96x+137=0 equation:

16x^2-96x+137=0

a = 16; b = -96; c = +137;
Δ = b2-4ac
Δ = -962-4·16·137
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-8\sqrt{7}}{2*16}=\frac{96-8\sqrt{7}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+8\sqrt{7}}{2*16}=\frac{96+8\sqrt{7}}{32}
$