16x2/4=72

Solution for 16x2/4=72 equation:

16x^2/4=72

We move all terms to the left:

16x^2/4-(72)=0

We multiply all the terms by the denominator


16x^2-72*4=0

We add all the numbers together, and all the variables

16x^2-288=0

a = 16; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·16·(-288)
Δ = 18432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18432}=\sqrt{9216*2}=\sqrt{9216}*\sqrt{2}=96\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{2}}{2*16}=\frac{0-96\sqrt{2}}{32}
=-\frac{96\sqrt{2}}{32}
=-3\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{2}}{2*16}=\frac{0+96\sqrt{2}}{32}
=\frac{96\sqrt{2}}{32}
=3\sqrt{2}
$