16x=-3(5x+2)+(2x-4)

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Solution for 16x=-3(5x+2)+(2x-4) equation:



16x=-3(5x+2)+(2x-4)
We move all terms to the left:
16x-(-3(5x+2)+(2x-4))=0
We calculate terms in parentheses: -(-3(5x+2)+(2x-4)), so:
-3(5x+2)+(2x-4)
We multiply parentheses
-15x+(2x-4)-6
We get rid of parentheses
-15x+2x-4-6
We add all the numbers together, and all the variables
-13x-10
Back to the equation:
-(-13x-10)
We get rid of parentheses
16x+13x+10=0
We add all the numbers together, and all the variables
29x+10=0
We move all terms containing x to the left, all other terms to the right
29x=-10
x=-10/29
x=-10/29

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