16x=0.25x2

Solution for 16x=0.25x2 equation:

16x=0.25x^2

We move all terms to the left:

16x-(0.25x^2)=0

We get rid of parentheses

-0.25x^2+16x=0

a = -0.25; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-0.25)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-0.25}=\frac{-32}{-0.5}
=+64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-0.25}=\frac{0}{-0.5}
=0
$