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16x=11/5x=1
We move all terms to the left:
16x-(11/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
16x-(+11/5x)=0
We get rid of parentheses
16x-11/5x=0
We multiply all the terms by the denominator
16x*5x-11=0
Wy multiply elements
80x^2-11=0
a = 80; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·80·(-11)
Δ = 3520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3520}=\sqrt{64*55}=\sqrt{64}*\sqrt{55}=8\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{55}}{2*80}=\frac{0-8\sqrt{55}}{160} =-\frac{8\sqrt{55}}{160} =-\frac{\sqrt{55}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{55}}{2*80}=\frac{0+8\sqrt{55}}{160} =\frac{8\sqrt{55}}{160} =\frac{\sqrt{55}}{20} $
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