16x=48/x=3

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Solution for 16x=48/x=3 equation:



16x=48/x=3
We move all terms to the left:
16x-(48/x)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
16x-(+48/x)=0
We get rid of parentheses
16x-48/x=0
We multiply all the terms by the denominator
16x*x-48=0
Wy multiply elements
16x^2-48=0
a = 16; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·16·(-48)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*16}=\frac{0-32\sqrt{3}}{32} =-\frac{32\sqrt{3}}{32} =-\sqrt{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*16}=\frac{0+32\sqrt{3}}{32} =\frac{32\sqrt{3}}{32} =\sqrt{3} $

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