16x=8x(x+10)

Solution for 16x=8x(x+10) equation:

16x=8x(x+10)

We move all terms to the left:

16x-(8x(x+10))=0


We calculate terms in parentheses: -(8x(x+10)), so:

8x(x+10)

We multiply parentheses

8x^2+80x

Back to the equation:

-(8x^2+80x)


We get rid of parentheses

-8x^2+16x-80x=0

We add all the numbers together, and all the variables

-8x^2-64x=0

a = -8; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·(-8)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*-8}=\frac{128}{-16}
=-8
$